27x^2y^2-3y^2=0

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Solution for 27x^2y^2-3y^2=0 equation:


Simplifying
27x2y2 + -3y2 = 0

Solving
27x2y2 + -3y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3y2' to each side of the equation.
27x2y2 + -3y2 + 3y2 = 0 + 3y2

Combine like terms: -3y2 + 3y2 = 0
27x2y2 + 0 = 0 + 3y2
27x2y2 = 0 + 3y2
Remove the zero:
27x2y2 = 3y2

Divide each side by '27y2'.
x2 = 0.1111111111

Simplifying
x2 = 0.1111111111

Take the square root of each side:
x = {-0.333333333, 0.333333333}

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